5*sin^2(x)-10*cos(2x)=0

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Solution for 5*sin^2(x)-10*cos(2x)=0 equation: 


Simplifying
5sin2(x) + -10cos(2x) = 0

Multiply in2s * x
5in2sx + -10cos(2x) = 0

Remove parenthesis around (2x)
5in2sx + -10cos * 2x = 0

Reorder the terms for easier multiplication:
5in2sx + -10 * 2cos * x = 0

Multiply -10 * 2
5in2sx + -20cos * x = 0

Multiply cos * x
5in2sx + -20cosx = 0

Reorder the terms:
-20cosx + 5in2sx = 0

Solving
-20cosx + 5in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5in2sx' to each side of the equation.
-20cosx + 5in2sx + -5in2sx = 0 + -5in2sx

Combine like terms: 5in2sx + -5in2sx = 0
-20cosx + 0 = 0 + -5in2sx
-20cosx = 0 + -5in2sx
Remove the zero:
-20cosx = -5in2sx

Divide each side by '-20osx'.
c = 0.25in2o-1

Simplifying
c = 0.25in2o-1

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